Robertson enters into Welsh Open snooker final

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Date: Feb. 17, 2007
Publisher: COMTEX News Network, Inc.
Document Type: Brief article
Length: 258 words
Lexile Measure: 2000L

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LONDON, Feb 17, 2007 (Xinhua via COMTEX) -- Neil Robertson of Australia moved into the final of Welsh Open when he scored 6-3 win over Steve Davis on Saturday.

The Melbourne player will face England's Andrew Higginson who knocked out Stephen Maguire 6-3 in the second semi-final.

Robertson, who won the London Grand Prix, hopes to become the first player for two years to win two ranking titles in the same season.

"That would be a great achievement because the standard is so high," said the 25-year-old Cambridge-based potter.

"It would also be a fantastic way to build towards the Crucible (for the world championship).

"I had to concentrate hard today and maintain my focus and my shot selection was pretty good. I had to kill the match off when I got the chance because Steve has made a lot of great comebacks."

Davis, the 49-year-old who was bidding for his first ranking title in 12 years, started well by taking the opening frame.

But a missed red in the second gave Robertson the opening to take it with runs of 42 and 41. The Aussie then pulled away to lead 4-1 with 70, 109 and 79.

Davis came from 51-0 down to take frame six with a 54 clearance before losing a scrappy seventh. He kept his hopes alive with a 91 for 5-3 but Robertson completed victory in the next in three scoring visits.

The left-hander has now beaten three snooker legends in succession - Stephen Hendry, Ronnie O'Sullivan and Davis.

Copyright 2007 XINHUA NEWS AGENCY.

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Gale Document Number: GALE|A159468663